(6x^3/y^2)*(5y^3/2x^2)*(4/15x^-2*y^-3)

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Solution for (6x^3/y^2)*(5y^3/2x^2)*(4/15x^-2*y^-3) equation: 


D( x )

x = 0

y^2 = 0

x = 0

x = 0

y^2 = 0

y^2 = 0

y^2 = 0

x naleu017Cy do R

x belongs to the empty set

(4/15)*x^-2*x^2*((6*x^3)/(y^2))*y^-3*((5*y^3)/2) = 0

x belongs to the empty set

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